Write the equation of the line that passes through (1, 5) and (−2, 14) in the slope-intercept form.a- y = 3x + 2b- y = 3x + 8c-y = −3x − 2d- y = −3x + 8

Answer:dStep-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Calculate m using the slope formulam = (y₂ - y₁ ) / (x₂ - x₁ )with (x₁, y₁ ) = (1, 5) and (x₂, y₂ ) = (- 2, 14)m = [tex]\frac{14-5}{-2-1}[/tex] = [tex]\frac{9}{-3}[/tex] = - 3, thusy = - 3x + c ← is the partial equationTo find c substitute either of the 2 points into the partial equationUsing (1, 5), then5 = - 3 + c ⇒ c = 5 + 3 = 8y = - 3x + 8 → d