The length of a rectangular room is 5 feet more than its width. The perimeter of the room is66 feet. Let L represent the length of the room and W represent the width in feet. The system of equationsL=W + 5can be used to represent this situation. What are the room's dimensions?166 = 2L + 2W
Accepted Solution
A:
Answer:[tex]\displaystyle 39 = W \\ 44 = L[/tex]Step-by-step explanation:{L = W + 5{166 = 2L + 2W166 = 2[W + 5] + 2W166 = 2W + 10 + 2W166 = 10 + 4W- 10 - 10___________[tex]\displaystyle \frac{156}{4} = \frac{4W}{4}[/tex][tex]\displaystyle 39 = W[/tex][Plug this back into both equations above to get the length of 44 feet; [tex]\displaystyle 44 = L[/tex]I am joyous to assist you anytime.